RS Aggarwal Class 10 Solutions Triangles
APlusTopper.com Provides RS Aggarwal Class 10 Solutions with Free PDF download option. All questions are solved by expert Mathematic Teachers as per NCERT (CBSE) guidelines.
Question 1:
(i) In ∆ABC, DE || BC, AD = 3.6 cm, AB = 10 cm, AE = 4.5 cm
Hence, AC = 12.5 cm and EC = 8cm
(ii) In ∆ABC, DE || BC, AB = 13.3 cm, AC = 11.9 cm and EC = 5.1 cm
Hence, AD = 7.7 cm
(iii) In ∆ABC, DE || BC, AC = 6.6 cm, [latex s=2]\frac { AD }{ DB } =\frac { 4 }{ 7 } [/latex]
Hence, AE = 2.4 cm
(iv) In ∆ABC, DE || BC, Given [latex s=2]\frac { AD }{ AB } =\frac { 8 }{ 15 } [/latex], EC=3.5cm
Hence AE = 4 cm
APlusTopper.com Provides RS Aggarwal Class 10 Solutions with Free PDF download option. All questions are solved by expert Mathematic Teachers as per NCERT (CBSE) guidelines.
Question 1:
(i) In ∆ABC, DE || BC, AD = 3.6 cm, AB = 10 cm, AE = 4.5 cm
Hence, AC = 12.5 cm and EC = 8cm
(ii) In ∆ABC, DE || BC, AB = 13.3 cm, AC = 11.9 cm and EC = 5.1 cm
Hence, AD = 7.7 cm
(iii) In ∆ABC, DE || BC, AC = 6.6 cm, [latex s=2]\frac { AD }{ DB } =\frac { 4 }{ 7 } [/latex]
Hence, AE = 2.4 cm
(iv) In ∆ABC, DE || BC, Given [latex s=2]\frac { AD }{ AB } =\frac { 8 }{ 15 } [/latex], EC=3.5cm
Hence AE = 4 cm
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